#### Answer

(c) it is reduced to one-ninth of its original value.

#### Work Step by Step

$F=k\frac{q_{1}q_{2}}{r^{2}}$
When the distance is tripled,
New Force=$k\frac{q_{1}q_{2}}{(3r)^{2}}=\frac{1}{9}F$
Hence, (c) is the answer.

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Published by
Pearson

ISBN 10:
0-32160-183-1

ISBN 13:
978-0-32160-183-4

(c) it is reduced to one-ninth of its original value.

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